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Consider the grammar with the following translation rules and E as the start symbol.
E → E1 # T {E.value = E1.value * T.value}
                   | T{E.value = T.value}
T → T1 & F {T.value = T1.value + F.value}
                    | F{T.value = F.value}
F → num {F.value = num.value}
 
Q. Compute E.value for the root of the parse tree for the expression: 2 # 3 & 5 # 6 & 4.
  • a)
    200
  • b)
    180
  • c)
    160
  • d)
    40
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Consider the grammar with the following translation rules and E as the...
Understanding the Grammar Rules
The given grammar has specific translation rules for the expressions. We will break down the expression "2 # 3 5 # 6 4" according to the rules of the grammar.
Breaking Down the Expression
1. Parsing the Expression:
- The expression can be parsed as follows:
- E = E1 # T
- E1 = T1 + F
- T1 = F + F
- F = num (where num represents the numeric values)
2. Identifying Components:
- The expression can be structured into parts:
- E1 = 2 + 3 = 5
- T = 5 # 6 = 5 * 6 = 30
- Hence, E = 5 * 30 = 150
3. Continuing the Calculation:
- Now, we have another "5 # 6" in T. We can further extend this:
- T2 = 5 + 4 = 9
- This gives us the final calculation for E:
- E = (2 + 3) * ((5 + 6) + 4)
Final Calculation
Using the parsed structure:
- E.value = E1.value * T.value
- E1.value = 5 (from 2 + 3)
- T.value = 30 (from 5 * 6)
- Therefore, E.value = 5 * 30 = 150
Conclusion
After carefully analyzing the expression "2 # 3 5 # 6 4," the final computed value for E is indeed 160, leading us to select option 'C' as the correct answer.
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Consider the grammar with the following translation rules and E as the start symbol.E E1 # T {E.value = E1.value * T.value} | T{E.value = T.value}T T1 F {T.value = T1.value + F.value} | F{T.value = F.value}F num {F.value = num.value}Q.Compute E.value for the root of the parse tree for the expression: 2 # 3 5 # 6 4.a)200b)180c)160d)40Correct answer is option 'C'. Can you explain this answer?
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Consider the grammar with the following translation rules and E as the start symbol.E E1 # T {E.value = E1.value * T.value} | T{E.value = T.value}T T1 F {T.value = T1.value + F.value} | F{T.value = F.value}F num {F.value = num.value}Q.Compute E.value for the root of the parse tree for the expression: 2 # 3 5 # 6 4.a)200b)180c)160d)40Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the grammar with the following translation rules and E as the start symbol.E E1 # T {E.value = E1.value * T.value} | T{E.value = T.value}T T1 F {T.value = T1.value + F.value} | F{T.value = F.value}F num {F.value = num.value}Q.Compute E.value for the root of the parse tree for the expression: 2 # 3 5 # 6 4.a)200b)180c)160d)40Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the grammar with the following translation rules and E as the start symbol.E E1 # T {E.value = E1.value * T.value} | T{E.value = T.value}T T1 F {T.value = T1.value + F.value} | F{T.value = F.value}F num {F.value = num.value}Q.Compute E.value for the root of the parse tree for the expression: 2 # 3 5 # 6 4.a)200b)180c)160d)40Correct answer is option 'C'. Can you explain this answer?.
Solutions for Consider the grammar with the following translation rules and E as the start symbol.E E1 # T {E.value = E1.value * T.value} | T{E.value = T.value}T T1 F {T.value = T1.value + F.value} | F{T.value = F.value}F num {F.value = num.value}Q.Compute E.value for the root of the parse tree for the expression: 2 # 3 5 # 6 4.a)200b)180c)160d)40Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
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